Documentation

Lean.Meta.Tactic.Simp.Main

Helper method for bootstrapping purposes. It disables arith if support theorems have not been defined yet.

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Similar to Result.getProof, but adds a mkExpectedTypeHint if proof? is none (i.e., result is definitionally equal to input), but we cannot establish that source and r.expr are definitionally when using TransparencyMode.reducible.

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Return true if e is of the form ofNat n where n is a kernel Nat literal

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  • Lean.Meta.Simp.instInhabitedM = { default := fun x x x => default }
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Given the application e, remove unnecessary casts of the form Eq.rec a rfl and Eq.ndrec a rfl.

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Try to use automatically generated congruence theorems. See mkCongrSimp?.

Process the given congruence theorem hypothesis. Return true if it made "progress".

Try to rewrite e children using the given congruence theorem

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@[inline]
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def Lean.Meta.Simp.main (e : Lean.Expr) (ctx : Lean.Meta.Simp.Context) (usedSimps : optParam Lean.Meta.Simp.UsedSimps ) (methods : optParam Lean.Meta.Simp.Methods { pre := fun e => pure (Lean.Meta.Simp.Step.visit { expr := e, proof? := none, dischargeDepth := 0 }), post := fun e => pure (Lean.Meta.Simp.Step.done { expr := e, proof? := none, dischargeDepth := 0 }), discharge? := fun x => pure none }) :
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def Lean.Meta.Simp.dsimpMain (e : Lean.Expr) (ctx : Lean.Meta.Simp.Context) (usedSimps : optParam Lean.Meta.Simp.UsedSimps ) (methods : optParam Lean.Meta.Simp.Methods { pre := fun e => pure (Lean.Meta.Simp.Step.visit { expr := e, proof? := none, dischargeDepth := 0 }), post := fun e => pure (Lean.Meta.Simp.Step.done { expr := e, proof? := none, dischargeDepth := 0 }), discharge? := fun x => pure none }) :
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Return true if e is of the form (x : α) → ... → s = t → ... → False

Recall that this kind of proposition is generated by Lean when creating equations for functions and match-expressions with overlapping cases. Example: the following match-expression has overlapping cases.

def f (x y : Nat) :=
  match x, y with
  | Nat.succ n, Nat.succ m => ...
  | _, _ => 0

The second equation is of the form

(x y : Nat) → ((n m : Nat) → x = Nat.succ n → y = Nat.succ m → False) → f x y = 0

The hypothesis (n m : Nat) → x = Nat.succ n → y = Nat.succ m → False is essentially saying the first case is not applicable.

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Tries to solve e using unifyEq?. It assumes that isEqnThmHypothesis e is true.

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Auxiliary method. Given the current target of mvarId, apply r which is a new target and proof that it is equal to the current one.

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See simpTarget. This method assumes mvarId is not assigned, and we are already using mvarIds local context.

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Simplify the given goal target (aka type). Return none if the goal was closed. Return some mvarId' otherwise, where mvarId' is the simplified new goal.

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Apply the result r for prop (which is inhabited by proof). Return none if the goal was closed. Return some (proof', prop') otherwise, where proof' : prop' and prop' is the simplified prop.

This method assumes mvarId is not assigned, and we are already using mvarIds local context.

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Simplify prop (which is inhabited by proof). Return none if the goal was closed. Return some (proof', prop') otherwise, where proof' : prop' and prop' is the simplified prop.

This method assumes mvarId is not assigned, and we are already using mvarIds local context.

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Simplify simp result to the given local declaration. Return none if the goal was closed. This method assumes mvarId is not assigned, and we are already using mvarIds local context.

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